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The true stress (in MPa) versus true strain relationship for a metal is given by

\(\sigma = 1020{\varepsilon ^{0.4}}\)

The cross-sectional area at the start of a test (when the stress and strain values are equal to zero) is 100 mm2. The cross-sectional area at the time of necking (in mm2) is ________ (correct to two decimal places)

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Best answer

Concept:

The relationship between true stress and strain is governed by the equation 

σ = σ0 ϵη

At UTS, ϵ = n

ϵ = True strain \(= \ln \left( {\frac{{{L_f}}}{{{L_i}}}} \right)\)

Where (Lf) is the final length; (Li) is the initial length.

Calculation:

Here σ = 1020 ε0.4

So ϵ = 0.4 at (UTS)

\(\Rightarrow 0.4 = \ln \left( {\frac{{{L_f}}}{{{L_i}}}} \right) \Rightarrow \frac{{{L_f}}}{{{L_i}}} = {e^{0.4}}\)

\(\Rightarrow \frac{{{L_f}}}{{{L_i}}} = 1.491\)

As volume remains constant throughout

(AiLi = Af Lf) Given Ai = 100 mm2

⇒ 100 Li = Af Lf

\(\Rightarrow {A_f} = 100 \times \frac{{{L_i}}}{{{L_f}}} \Rightarrow {A_f} = \frac{{100}}{{1.49}}\)

Af = 67.03 mm2

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