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The value of ∫ [x^3 + 3x^2 + 3x + 3 + (x + 1)cos (x + 1)] (for x → -2,0) dx is

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The value of ∫ [x3 + 3x2 + 3x + 3 + (x + 1)cos (x + 1)] (for x → -2,0) dx is

(a) 0

(b) 3

(c) 4

(d) 1

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1 Answer

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Best answer

Correct option (c) 4

Explanation :

(Since, t3 and t cos t are odd functions)

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