Question

Sun’s surface at 5800 K emits radiation at a wavelength of 0.5 μA. A furnace at 300°C will emit through a small opening, radiation at a wavelength of
1. 5 μ
2. 0.5 μ
3. 2.5 μ
4. 0.25 μ

Answer 1

Correct Answer - Option 1 : 5 μ

 T_s = 5800 K

λ = 0.5 μA

T = 300° C

\(\lambda \propto \frac{1}{T}\)

⇒ λ₁T₁ = λ₂ T₂

⇒ 0.5 × 5800 = λ₂ × (300 + 273)

λ₂ = 5.06 μ