Correct Answer - Option 3 : 19.8 × 10
- 6/°C
The length of iron rod at 150°C is
Liron = Lo (1 + αθ)
= 70[1 + 12 × 10 - 6 × (150 - 30)] = 70.1008 cm
Length of aluminium rod at 150°C
lAl = 130 (1 + 24 × 10 - 6 × (150 - 30)) = 130.3744 cm
The length of composite system at 150°C is
70.1008 + 130.3744 = 200.4752 cm
Average coefficient of linear expansion
\(\alpha = \frac{{200.4752 - 200}}{{200\; \times \;\left( {150 - 30} \right)}}\) = 1.98 × 10 - 5/°C
= 19.8 × 10
- 6/°C