Q = 0.01 m3/s
d = 100 mm
Re = 800
g = 9.81 m/s2
\({h_f} = \frac{{fl{V^2}}}{{2gd}}\)
Since Re is less than 2000 the flow will be laminar flow
Hence, \(f = \frac{{64}}{{{R_e}}} = 0.08\)
\(\begin{array}{l} {h_f} = \frac{{fl{Q^2}}}{{12.1{d^5}}}\\ = \frac{{0.08 \times 1000 \times \left( {0.01} \right)2}}{{12.1 \times {{\left( {0.1} \right)}^5}}} = 66.10\;m \end{array}\)