Component
(1)
|
% By Mass
(2)
|
Moisture content
(%)
(3)
|
dry content %
(4)
= 100 – (3)
|
Energy
discarded
(5)
(kJ / kg)
|
Total dry mass
(6)
\(\frac{{\left( 2 \right) \times \left( 4 \right)}}{{100}}\)
|
Total energy as
discarded
\(\frac{{\left( 2 \right) \times \left( 5 \right)}}{{100}}\)
|
Food Waste
|
20
|
70
|
30
|
2500
|
6
|
500
|
Paper
|
10
|
4
|
96
|
10000
|
9.6
|
1000
|
Cardboard
|
10
|
4
|
96
|
8000
|
9.6
|
800
|
Plastics
|
10
|
1
|
99
|
14000
|
9.9
|
1400
|
Garden Trimmings
|
40
|
60
|
40
|
3500
|
16
|
1400
|
Wood
|
5
|
20
|
80
|
14000
|
4
|
700
|
Tin Cans
|
5
|
2
|
98
|
10
|
4.9
|
5
|
|
= 60
|
= 5805 kJ/kg
|
Energy on dry basis: It will be the total energy when whole mass is dry.
In current situation only 60% mass is dry, so energy corresponding to 60% dry mass = 5805 kJ/kg
Using unitary method, energy corresponding to 100% dry mass \(= \frac{{5805}}{{60}} \times 100\) = 9675 kJ/kg
Energy based on as discarded basis = 5805 kJ/kg
So, difference = 9675 – 5805 = 3870 kJ/kg