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While aligning a hill road with a ruling gradient of 6%, a horizontal curve of radius 50 m is encountered. The grade compensation (in percentage up two equal places) to be provided for this case would be _______

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R = 50

Grade compensation \(= \frac{{30 + {\rm{R}}}}{{\rm{R}}} = \frac{{30 + 50}}{{50}} = \frac{{80}}{{50}} = 1.6\)

(Grade compensation)max \(= \frac{{75}}{{\rm{R}}} = \frac{{75}}{{50}} = 1.5\)

Grade compensation should not be more than (Grade compensation)max

Hence, (grade compensation)max = 1.5

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