Question

Four iron rings P, Q, R, S having the same density, but different radius, P = 5r/2, Q = 2r, R = 7r/4, S = 3r sinks in the honey. Which one of the order is correct starting from reaching first at bottom of the surface?
1. R, P, Q, S
2. R, Q, P, S
3. S, P, Q, R
4. S, Q, P, R

Answer 1

Correct Answer - Option 3 : S, P, Q, R

As the density is same for all four rings, so mass is directly proportional to the volume of the ring which will depend on the radius of the ring. So the ring having higher radius will reach first. So the order will be S, P, Q and R.