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At what depth below the free surface of oil having a density of 784 kg/m3 will the pressure be very nearly equal to 1 bar?
1. 10 metres
2. 14 metres
3. 13 metres
4. 7.84 metres

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Correct Answer - Option 3 : 13 metres

Solution:

At a depth 'h' below the free surface of a liquid of density 'ρ', the pressure is given by 

P = ρgh

Given P = 1 bar = 105 Pa, ρ = 784 kg/m3

⇒ 1 × 105 = 784 × 9.81 × h

∴ h ≈ 13 m

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