Question

Electric field intensity between plates of a parallel plate condenser is E. Now if a dielectric of medium of dielectric constant ϵ is introduced between the plates, the electric field intensity will become
1. ϵE
2. E/ϵ
3. \(\sqrt{ϵE}\)
4. \(\sqrt{(\frac{E}{ϵ})}\)

Answer 1

Correct Answer - Option 2 : E/ϵ

After introduction of dielectric slab, capacitance of the condenser increases while the electric field decreases by the factor of dielectric constant.