Correct Answer - Option 3 : 506
Concept:
The sum of ‘n’ terms of an AP
\(S_n = \frac{n}{2}\left[ {2a + \left( {n - 1} \right)d} \right]\)
Calculation:
Given:
AP is 44, 42,- - - - - 2.
n = 22, a = 2 and d = 2
The sum of ‘n’ terms of an AP
\(S_n= \frac{n}{2}\left[ {2a + \left( {n - 1} \right)d} \right]\)
Sn = 11[4 + (21 × 2)] = 11 × 46 = 506
