Correct Answer - Option 2 : 19/144
n = 4, P = 1/6 = Prob. of ‘six’
then prob of failure (other than ‘six’) \(= 1 - \frac{1}{6} = \frac{5}{6}\)
P(x ≥ 2) = 1 – P (x < 2)
= 1 – P (0) – P (1)
\(= 1 - {{\rm{4}}_{{C_0}}}{\left( {\frac{1}{6}} \right)^0}{\left( {\frac{5}{6}} \right)^4}{ + ^4}{C_1}{\left( {\frac{1}{6}} \right)^1}{\left( {\frac{5}{6}} \right)^3} = \frac{{19}}{{144}}\)
