Correct Answer - Option 2 :
\(\frac{1}{4}\)
Given that,
Probability that Ram is selected ⇒ \({P_1} = \frac{1}{6}\)
Probability that Ramesh is selected ⇒ \({P_2} = \frac{1}{8}\)
Probability that only one of them is selected = P
\(\begin{array}{l} P = {P_1} \times \overline {{P_2}} + {P_2} \times \overline {{P_1}} \\ = \frac{1}{6} \times \left( {1 - \frac{1}{8}} \right) + \frac{1}{8} \times \left( {1 - \frac{1}{6}} \right)\\ = \frac{{12}}{{40}} = \frac{1}{4} \end{array}\)