Correct Answer - Option 3 : 58.20%
SI engine
clearance volume, VC = 0.001 m2
stroke length, L = 250 mm = 0.25 m
bore dia, d = 200 mm = 0.2 m
specific heat ratio, γ = 1.4
\(Stroke\;Volume,\;\;{V_s} = \frac{\pi }{4}{D^2}L \\= \frac{\pi }{4} \times {0.2^2} \times 0.25 = 0.00785\)
\(Compression\;Ratio\;,r = 1 + \frac{{{V_s}}}{{{V_c}}} \\= 1 + \frac{{0.00785}}{{0.001}} = 8.85\)
\(efficiency\;\;\eta = 1 - \frac{1}{{{r^{{\rm{\gamma }} - 1}}}}\)
\(= 1 - \frac{1}{{{{8.85}^{\left( {1.4 - 1} \right)}}}}\)
\(= 1 - \frac{1}{{{{8.85}^{0.4}}}}\)
= 0.5819
η ≈ 58.20%