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A dice is thrown. Find the difference of the probability that the number is a prime number and composite number?
1. \( \rm \frac{2}{3}\)
2. \( \rm \frac{1}{5}\)
3. \( \rm \frac{1}{6}\)
4. \( \rm \frac{5}{6}\)

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Correct Answer - Option 3 : \( \rm \frac{1}{6}\)

Concept:

Prime Number - A natural number greater than 1 which has only 1 and itself as factors.

Composite Number - A natural number greater than 1 which has more factors than 1 and itself.

Calculation:

On a through of a dice 6 possible outcomes are possible. They are (1, 2, 3, 4, 5, 6)

Among which only 4 and 6 are composite numbers that is two numbers are composite

The probability of getting a composite number on the throw of dice is \(\rm \frac{2}{6} = \frac{1}{3}\)

2, 3 and 5 are prime numbers that is three numbers are prime

The probability of getting a prime number on the throw of dice is \(\rm \frac{3}{6} = \frac{1}{2}\)

The difference of the probability that the number is a prime number and composite number is \(\rm \frac{1}{2} - \frac{1}{3} = \frac{1}{6}\)

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