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If a2 + c2 + 17 = 2(a - 8b - 2b2) then what is the value of (a3 + b3 + c3) ?
1. -7
2. -4
3. 10
4. 9

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Correct Answer - Option 1 : -7

Given:

 a2 + c2 + 17 = 2(a - 8b - 2b2

calculation:

 a2 + c2 + 17 = 2(a - 8b - 2b2

⇒ a2 + c2 + 17 = 2a – 16b – 4b2

⇒ a2 + 4b2 + c2 + 17 = 2(a – 8b)

⇒ a2 – 2a + 1 + 4b2 + 16b + c2 = 0

⇒ (a – 1)2 + (2b + 4)2 + c2 = 0

⇒ a = 1, b = -2 and c = 0

Now,

(a3 + b3 + c3) = (1)3 + (-2)3 + (0)3

⇒ 1 – 8 + 0

⇒ -7

∴ The required value is -7

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