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Compute the heat generated while transferring 100 kC of charge in one hour through a potential difference of 75 V.
1. 7.5 MJ
2. 7.0 MJ
3. 8.4 MJ
4. 8.1 MJ

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Correct Answer - Option 1 : 7.5 MJ

Concept:

Electric field: The space or region around the electric charge in which electrostatic force can be experienced by other charged particles is called an electric field by that charge.

Electric potential difference: The amount of work done to move a unit charge from a point to another point in a space where an electric field is present is called an electric potential difference.

\({\rm{Potential\;difference}}\left( {\rm{V}} \right) = {\rm{\;}}\frac{{Work\;done\left( W \right)}}{{Charge\left( Q \right)}}\)

Work done (W) = Energy gained = Q V

Calculation:

Given:

Q = 100 kC = 105 C, V = 75 V

W = QV

W = 105 × 75

W = 75 × 105 

W = 7.5 MJ

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