Correct Answer - Option 2 : 3
Given:
30a68b (a > b) is divisible by 11
Concept:
If the difference between the sum of the digits at the odd and even places equal 0 or divisible by 11, the number is divisible by 11.
Calculation:
(3 + a + 8) - (0 + 6 + b) = 0 or 11
⇒ 11 + a - 6 - b = 0 or 11
⇒ 5 + a - b = 0 or 11
⇒ 5 + a - b ≠ 0 [a > b]
Let 5 + a - b = 11
⇒ a - b = 6
⇒ For a = 9, b = 3 ∵ [a > b]
⇒ 9 - 3 = 6
∴ The greatest value of b is 3, when 30a68b (a > b) is divisible by 11.
