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A vehicle travelling on dry, levelled pavement at 127 km/h had the brakes applied. The vehicle travelled 127 m before stopping. What is the coefficient of friction that has developed ?
1. 0.2
2. 0.3
3. 0.5
4. 0.55

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Correct Answer - Option 3 : 0.5

Concept:

Braking Distance:

It is the distance travelled by vehicle after the application of brakes.

Skid length or braking distance is given by, \({\rm{L}} = \frac{{{{\rm{u}}^2}}}{{2{\rm{gf}}}}\),

where u is the velocity of the vehicle in m/s, f is the actual coefficient of friction mobilized and g is the acceleration due to gravity.

Calculation:

Given,

Velocity of vehicle (u) = 127 kmph = 127/3.6 = 35.278 m/s

Braking distance (L) = 127 m

\({\rm{L}} = \frac{{{{\rm{u}}^2}}}{{2{\rm{gf}}}}\)

⇒ \({\rm{127}} = \frac{{{{\rm{35.278}}^2}}}{{2\ \times \ {\rm{9.81 \times f}}}}\)

f = 0.4994 ≈ 0.5

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