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What is the least number, which leaves the remainder 2 on dividing by numbers 7, 11, 14, 21, and 22?


1. 364
2. 674
3. 564
4. 464

1 Answer

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Best answer
Correct Answer - Option 4 : 464

Given:

A number leaves the remainder 2 on dividing by the numbers 7, 11, 14, 21 and 22.

Concept used:

Least number which leaves same remainder on dividing a, b, c, d and e = LCM of (a, b, c, d and e) + Remainder

Calculation:

LCM of 7, 11, 14, 21 and 22 = 462

Required number = LCM of 7, 11, 14, 21 and 22 + remainder

⇒ Required number = 462 + 2 = 464

∴ Required number is 464

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