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If in a flow field \(\frac{P}{\gamma} + \frac{v^2}{2g} + z \) = constant between any two points, flow must be
1. Steady, compressible and irrotational
2. Unsteady, incompressible and irrotational
3. Steady, incompressible and irrotational
4. Steady, compressible and along a steam line

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Correct Answer - Option 3 : Steady, incompressible and irrotational

Concept:

Bernoulli’s equation:

Bernoulli’s equation between any two points in the form of energy per unit weight is given by,

\(\frac{P}{\gamma} + \frac{v^2}{2g}\) + z = constant

The following are the assumptions made in the derivation of Bernoulli’s equation:
  • The fluid is ideal, i.e Viscosity is zero or inviscid
  • The flow is steady
  • The flow is incompressible
  • The flow is irrotational

  • Bernoulli's equation can be obtained by integrating Euler's equation as follows -

We know Euler's equation,

\(\frac{dP}{\rho}\) + vdv + gdz = 0

On intergrating, along a stream line between two points

\(\int\limits _1^2\)\(\frac{dP}{\rho}\)\(\int\limits _1^2\)vdv + \(\int\limits _1^2\)gdz = 0

\(\frac{P_1}{\rho} + \frac{v_1^2}{2} + gz_1 = \frac{P_2}{\rho} + \frac{v_2^2}{2} + gz_2\)

⇒  \(\frac{P}{\gamma} + \frac{v^2}{2g}\) + z = constant

Here,

\(\frac{P}{\gamma}\) - static head (m)

\(\frac{v^2}{2g}\) - Dynamics head (m)

z - datum head (m)

P - Pressure (Pa)

v - Average velocity (m/sec)

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