Correct Answer - Option 1 : 13.08 kN/m
3
Concept:
Dry unit weight, \({γ _d} = \frac{{G{γ _w}}}{{1 + e}}\)
Se = wG
Where,
S = saturation
w = water content
G = specific gravity
e = void ratio
Calculation:
Given,
w = 35 %, Gs = 2.5, γw = 9.81 kN/m3
S = 1 as given saturated soil
e = wG = 0.35 × 2.5 = 0.875
\({\gamma _d} = \frac{{2.5 \times 9.81}}{{1 + 0.875}} = 13.08\;kN/{m^3}\)