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A Si sample is doped with 1017 Arsenic atoms/cm3. Displacement of EF relative to Ei is ______
1. Positive, 0.589 eV
2. Negative, 0.589 eV
3. Positive, 0.407 eV
4. Negative, 0.407 eV

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Correct Answer - Option 3 : Positive, 0.407 eV

Concept:

Displacement of fermilevel with respect to intrinsic termi level is given by-

\({{\rm{E}}_{\rm{F}}} - {{\rm{E}}_{\rm{i}}} = {{\rm{K}}_{\rm{T}}}{\rm{In}}\left( {\frac{{{{\rm{N}}_{\rm{D}}}}}{{{{\rm{N}}_{\rm{i}}}}}} \right){\rm{\;or\;KT\;In}}\left( {\frac{{{{\rm{N}}_{\rm{A}}}}}{{{{\rm{n}}_{\rm{i}}}}}} \right)\)

Where ND = donor type doping concentration

NA = Acceptor type doping concentration

ni = intrinsic carrier concentration

Calculation:

Given N0 = 1017 / cm3 (Arsenic - Pentavalent- donor type)

ni = 1.5 × 1010 / cm3

displacement of EF relative to \({{\rm{E}}_{\rm{i}}} = {{\rm{K}}_{\rm{T}}}{\rm{In}}\left( {\frac{{{{\rm{N}}_{\rm{D}}}}}{{{{\rm{n}}_{\rm{i}}}}}} \right)\)

\({{\rm{E}}_{\rm{F}}} - {{\rm{E}}_{\rm{i}}} = .0258{\rm{In}}\left( {\frac{{{{10}^{17}}}}{{1.5\; \times \;100}}} \right)\)

EF – Ei = .407 ev

In donor type impurity EF shifts up with respect to intrinsic fermi level so it will be positive.

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