Correct Answer - Option 3 : Positive, 0.407 eV
Concept:
Displacement of fermilevel with respect to intrinsic termi level is given by-
\({{\rm{E}}_{\rm{F}}} - {{\rm{E}}_{\rm{i}}} = {{\rm{K}}_{\rm{T}}}{\rm{In}}\left( {\frac{{{{\rm{N}}_{\rm{D}}}}}{{{{\rm{N}}_{\rm{i}}}}}} \right){\rm{\;or\;KT\;In}}\left( {\frac{{{{\rm{N}}_{\rm{A}}}}}{{{{\rm{n}}_{\rm{i}}}}}} \right)\)
Where ND = donor type doping concentration
NA = Acceptor type doping concentration
ni = intrinsic carrier concentration
Calculation:
Given N0 = 1017 / cm3 (Arsenic - Pentavalent- donor type)
ni = 1.5 × 1010 / cm3
displacement of EF relative to \({{\rm{E}}_{\rm{i}}} = {{\rm{K}}_{\rm{T}}}{\rm{In}}\left( {\frac{{{{\rm{N}}_{\rm{D}}}}}{{{{\rm{n}}_{\rm{i}}}}}} \right)\)
\({{\rm{E}}_{\rm{F}}} - {{\rm{E}}_{\rm{i}}} = .0258{\rm{In}}\left( {\frac{{{{10}^{17}}}}{{1.5\; \times \;100}}} \right)\)
EF – Ei = .407 ev
In donor type impurity E
F shifts up with respect to intrinsic fermi level so it will be positive.