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A train A of length 2800 m crosses another train B of length 3500 m in 630/11 seconds. Train B crosses a platform of length 700 m in 60 seconds. Find the speed(in m/s) of train A. 
1. 48
2. 42
3. 40
4. 45

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Correct Answer - Option 3 : 40

Given:

A train A of length 2800 m crosses another train B of length 3500 m in 630/11 seconds. Train B cross a platform of length 700 m in 60 seconds

Formula:

If the lengths of two trains are a and b,

Time taken to cross each other when travelling in same direction = (a + b)/(va - vb)

Time taken to cross each other when travelling in opposite direction = (a + b)/(va + vb)

where va and vb are the speeds of trains A and B respectively.

Calculation:

Let the speeds of train A and B be a and b respectively.

(2800 + 3500)/(a + b) = 630/11       ----(1)

⇒ (3500 + 700)/b = 60

⇒ b  = 4200/60 = 70

Hence, speed of B is 70m/s

Putting b = 70 in equation 1, we get,

(2800 + 3500)/(a + 70) = 630/11

⇒ a = 40

Therefore, speed of train A is 40 m/s.

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