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For a process, the quality loss coefficient is 5. The target value on the dimension to be attained through the process is 50 mm. If the maximum loss permissible (in monetary terms) is INR 80, the maximum allowable deviation (in mm) from the target is
1. \(1\over 4\)
2. \(\sqrt{\frac{1}{10}}\)
3.  4
4. \(\sqrt{10}\)

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Correct Answer - Option 3 :  4

Concept:

R = \(\frac{A_0}{(Δ _0)^2}\)

where,

R = Quality loss coefficient

A0 = Economic Consequence

Δ0 = Functional Limit or Customer tolerance

Calculation:

Given:

R = 5, A 0 = 80, Δ0 = ?

Δ0 = \(\sqrt{\frac{A_0}{R}}\) = \(\sqrt{\frac{80}{5}}\) = \(\sqrt{16}\) = 4

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