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The efficiency of a Carnot engine is 50% and the sink temperature is 50 °C. Find the source temperature.
1. 373 K
2. 273 °C
3. 373 °C
4. 673 °C

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Best answer
Correct Answer - Option 3 : 373 °C

CONCEPT:

  • Carnot engine: The theoretical engine which works on the Carnot cycle is called a Carnot engine.
    • It gives the maximum possible efficiency among all types of heat engines.
  • Heat source: The part of the Carnot engine which provides heat to the engine is called a heat source.
    • The temperature of the source is maximum among all the parts.
  • Heat sink: The part of the Carnot engine in which an extra amount of heat is rejected by the engine is called a heat sink.
  • The amount of work that is done by the engine is called work done.

The efficiency (η)of a Carnot engine is given by:

\(η = 1 - \frac{{{T_C}}}{{{T_H}}} = \;\frac{{Work\;done\left( W \right)}}{{{Q_{in}}}} = \;\frac{{{Q_{in}} - \;{Q_R}}}{{{Q_{in}}}}\)

Where Tis the temperature of the sink, Tis the temperature of the source, W is work done by the engine, Qin is the heat given to the engine/heat input and QRis heat rejected.

The relation between the Kelvin scale (K) and the celsius scale (°C);

K = °C + 273

CALCULATION:

Given that:

η = 50 % = 0.5

Heat sink temperature (TC) = 50 °C = 273 + 50 = 323 K

Heat source temperature (T H) = ?

\(η = 1 - \frac{{{T_C}}}{{{T_H}}} \)

\(0.5 = 1 - \frac{{{323}}}{{{T_H}}} \)

323/TH = 0.5

TH = 323/0.5 = 646 K = 646 - 273 = 373 °C

Hence option 3 is correct.

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