Correct Answer - Option 1 : 73%
Given
Let pure milk = 100
Water is replaced in 10% in per process = 10% of 100 = 10 liter
Formula used
Quantity of Milk present after replacing = X × [1 - (Y/X)]n
here , X = initial quantity of milk , Y = replaced water in per process , n = no of process repeated
Calculation
Let pure milk = 100
Water is replaced in 10% in per process = 10% of 100 = 10 liter
Quantity of milk present = 100 × [1-10/100]3
⇒ 100 × [1-1/10]3
⇒ 100 × 729/1000
⇒ 72.9%
∴ The percentage of pure milk is present in the mixture is 73%.