Correct Answer - Option 1 : 1 / 6 unit
Calculation:
Given:
y = x2
y = x
Interconnection point,
x2 = x
x = 1, y = 1
Area Enclosed (A) is given by,
\(A=\mathop \smallint \limits_0^1 \left( {x - {x^2}} \right)dx\)
\(A = \left[ {\frac{{{x^2}}}{2} - \frac{{{x^3}}}{3}} \right]_0^1\)
\(A = \frac{1}{2} - \frac{1}{3}\)
\(A = \frac{1}{6}\) unit