Data : l = 30 cm = 0.3 m,
I = 5 A, B = 0.2 T, θ = 60°
The magnitude of the force on the conductor,
F = I\(\vec l\) x\(\vec B\)| = IlB sin θ
= (5 A) (0.3 m) (0.2 T) sin 60°
= 0.3 × 0.866 = 0.2598 N
The direction of the force is given by the cross product rule.