Correct Answer - Option 3 : 28 years
Given:
The sum of their ages is 64 years old
After 10 years, the age of father will be twice the age of his son
Calculations:
Let the age of father be ‘x’ years old
Let the age of son be ‘y’ years old
After 10 years,
The age of father will be (x + 10) years old
The age of son will be (y + 10) years old
According to question, we have
⇒ x + 10 = 2(y + 10)
⇒ x + 10 = 2y + 20
⇒ x – 2y = 10 ----(1)
And, x + y = 64 ----(2)
From (1) and (2), we get
⇒ y = 18 years
So, the age of son is 18 years old
Put y = 18 in equation (2), we get
⇒ x = 46 years
So, the age of father is 46 years old
Difference between their ages is
⇒ 46 – 18 = 28 years
∴ The difference between the ages of father and son is 28 years.