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+1 vote
6.8k views
in Physics by (70.0k points)

A bulb is connected to a battery of e.m.f. 6V and internal resistance 2Ω A steady current of 0.5A flows through the bulb. Calculate: 

(i) the total energy supplied by the battery in 10 minutes, 

(ii) the resistance of the bulb, 

(iii) the heat energy dissipated in the bulb in 10 minutes.

1 Answer

+1 vote
by (72.8k points)
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Best answer

Given: E = 6V, r = 2Ω, i = 0.5A, t = 10 minute = 10 × 60s = 600s.

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