Correct Answer - Option 1 : 104°F
Concept:
\(\frac{{}_\;^ \circ C}{5}\; = \frac{{{}_\;^ \circ F\; - 32}}{9}\; = \frac{{T\; - 273.16}}{5}\)
Here, °C = Tempture in degree Celsius, °F = Tempture in degree Fehrenheit, T = Tempture in Kelvin
Calculation:
Given:
t = 40 °C
\(\frac{{40}}{5}\; = \;\frac{{^\circ F - 32}}{9}\)
°F - 32 = 72
°F = 104 °F
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The triple point of water: It is the point where all the phases coexist.
- For water its value is 273.16 = 0.01 °C
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Triple point pressure = 611.2 Pa = 4.58 mm of Hg.
