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If specific volume of any material is 0.000112 m3/kg, then calculate the specific gravity of that material.
1. 8.92
2. 8.52
3. 9.81
4. 7.8

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Correct Answer - Option 1 : 8.92

Concept:

Density (ρ): It is the ratio of mass per unit volume.

\(ρ=\frac{mass}{volume}⇒\frac{m}{V}\) kg/m3

Specific gravity (S.G)The specific gravity of a liquid is the relative weight of that liquid compared to an equal volume of water.

\(S.G= \frac{{Density\;of\;liquid}}{{Density\;of\;water}}⇒\frac{ρ}{ρ_w}\)

Specific volume (ν): It is the ratio of volume per unit mass.

\(\nu=\frac{volume}{mass}⇒\frac{V}{m}=\frac{1}{ρ}\) m3/kg

Calculation:

Given:

v = 0.000112 m3/kg.

\(\nu=\frac{V}{m}=\frac{1}{ρ}\)

\(0.000112=\frac{1}{ρ}\)

\(112\times10^{-6}=\frac{1}{ρ}\)

\(\rho=\frac{1}{112\times10^{-6}}=\frac{10^6}{112}\) kg/m3.

\(S.G= \frac{{Density\;of\;liquid}}{{Density\;of\;water}}⇒\frac{ρ}{ρ_w}\)

\(S.G= \frac{{Density\;of\;liquid}}{{Density\;of\;water}}⇒\frac{\frac{10^6}{112}}{1000}=\frac{1000}{112}=8.928\)

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