Correct Answer - Option 1 : 3 : 4
Given
The areas of two similar triangles are in the ratio of 9 : 16
Concept used
The ratio of areas = Ratio of squares of corresponding sites
Calculation
Let Δ ABC and Δ PQR be two similar triangles.
Area of two similar triangles are in the ratio 9 : 16
⇒ \(\frac{{\Delta ABC}}{{\Delta PQR}} = \frac{{{{\left( {AB} \right)}^2}}}{{{{\left( {PQ} \right)}^2}}}\)
⇒ \(\frac{9}{{16}} = \frac{{{{\left( {AB} \right)}^2}}}{{{{\left( {PQ} \right)}^2}}}\)
⇒ \(\frac{{AB}}{{PQ}} = \sqrt {\frac{9}{{16}}} \)
⇒ \(\frac{{AB}}{{PQ}} = \frac{3}{4}\)