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If secθ - cosθ = 1/2, find the value of sin2θ when θ lies in first quadrant.


1. (√15 – 6)/8
2. (√17 – 3)/8
3. (√17 – 1)/8
4. (√14 – 7)/8

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Best answer
Correct Answer - Option 3 : (√17 – 1)/8

Given:

secθ - cosθ = 1/2

Concepts used:

sin2θ + cos2θ = 1

secθ = 1/cosθ

Calculation:

secθ - cosθ = 1/2

⇒ (1/cos2θ) – cosθ = 1/2

⇒ 1 – cos2θ = cosθ/2

⇒ 2 – 2cos2θ – cosθ = 0 

⇒ 2cos2θ + cosθ – 2 = 0

θ lies in 1st quadrant

⇒ cosθ is positive in first quadrant.

⇒ cosθ = (√17 – 1)/4

sin2θ =  1 – cos2θ

⇒ sin2θ = 1 – {(√17  - 1)/4}2

⇒ sin2θ = 1 – {(9 - √17)/8}

⇒ sin2θ = (√17 – 1)/8

∴ Value of sin2θ is (√17 – 1)/8.  

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