Correct Answer - Option 1 : 5
Concept:
Formula used:
If f(x) = xn, then f'(x) = n xn - 1
Calculations:
Given:
\(\rm f(x) = 2x^3+ \dfrac{1}{x}\)
Differentiating with respect to x, we get
⇒ f'(x) = 6x2 - \(\frac{1}{x^2}\)
Put x = 1
f'(x) = 6 × 12 - \(\frac{1}{1^2}\)
f'(-1) = 6 - 1 = 5
∴ The value of f'(1) is 5