Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
169 views
in Physics by (114k points)
closed by
A motorcyclist is riding on a highway. At a certain location he takes a U-turn in 6.25 seconds. The angular velocity during the turn is-
1. 0.5 rad/s
2. 0.2 rad/s
3. 0.3 rad/s
4. 0.4 rad/s

1 Answer

0 votes
by (113k points)
selected by
 
Best answer
Correct Answer - Option 1 : 0.5 rad/s

The correct answer is option 1) i.e. 0.5 rad/s

CONCEPT:

  • Angular velocity is the velocity associated with objects moving in a curved path.
    • While on a curved path, the displacement is the change in angle about the point of rotation or curved motion.

Angular velocity, \(ω =\frac{angle}{time} =\frac{dθ}{dt}\)

  • The tangent to any point on the curved path gives the direction of the linear velocity of the object at that point.
  • The angular velocity ω is related to the linear velocity of an object v by the equation

v = rω 

Where r is the radius of the curvature.

EXPLANATION:

  • Angle covered by the motorcyclist in U-turn, θ = 180∘ = π radian

Time taken to cover π radian,t = 6.25 s

Angular velocity, \(ω =\frac{dθ}{dt} = \frac{\pi}{6.25} =0.5 \: rad/s\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...