Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.4k views
in Sets, Relations and Functions by (114k points)
closed by
Find the range of the real function f(x) = \(\rm \frac{x+1}{x-3}\)
1. R - {3}
2. R - {1}
3. R 
4. R - {-3}
5. None of these

1 Answer

0 votes
by (113k points)
selected by
 
Best answer
Correct Answer - Option 2 : R - {1}

Concept:

Range: The range of a function is the set of all possible values it can produce, i.e., all values of y for which x is defined.

Calculation:

Let, y = f(x) = \(\rm \frac{x+1}{x-3}\)

⇒y(x - 3) = x + 1

⇒yx - 3y - x = 1

⇒ x(y - 1) - 3y = 1

⇒ x(y - 1) = 1 + 3y

\(\rm x = \frac{1+3y}{y-1}\)

It is clear that x is not defined when y - 1 = 0, i.e, when  y = 1

∴ Range (f) = R - {1}

Hence, option (2) is correct.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...