Correct Answer - Option 1 : It decreases with an increase in depth.
The correct answer is option 1) i.e. It decreases with an increase in depth.
CONCEPT:
-
Acceleration due to gravity: The acceleration produced on a body due to the gravitational pull of the Earth is called acceleration due to gravity.
It is given by the equation:
\(g = \frac{GM}{R^{2}}\)
where, g = Acceleration due to the gravity, G = Universal Gravitational Constant, M = Mass of the Earth, and R= Radius of the Earth
-
Variation of the value of "g":
-
The value of "g" varies with altitude above and depth below the surface of the Earth, with the shape of the Earth and with the rotation of the Earth about its axis.
EXPLANATION:
-
Variation of g with depth: The acceleration due to gravity at a depth "d", represented as gd is related to the acceleration due to gravity on the surface of the Earth "g" as:
\(g_{d} = \frac{g(R-d)}{R}\)
- Hence, with the increase in depth from the Earth's surface, the value of "g" decreases.
- The value of "g" decreases with an increase in altitude or height from the surface of the Earth.
- The value of "g" at the surface of the Earth is a constant and is approximately equal to 9.8 m/s2.
- The value of "g" becomes zero at the center of the Earth.
