Correct Answer - Option 2 : 2 only
Concept:
Determinant of a matrix:
For an \(\rm n\times n\) matrix \(A = \left[a_{ij}\right]\) the determinant of A is defined as to be a scaler
\(\rm det(A) = \displaystyle\sum_{p}\sigma(p)a_{1_{p_1}}a_{2_{p_2}}\dots a_{n_{p_n}}\)
where the sum is taken over n! permutations p = (\(\rm p_1, p_2,\dots, p_n\)) of (1, 2, 3, ... , n).
Calculation:
Observe that any matrix is a vector but determinant is a scaler. Therefore, determinant is not a square matrix.
For any square matrix A the determinant is a scaler associated with that matrix.
That means it is a number associated with a square matrix.