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If we throw a dice, what is the probability of obtaining a result that is less than 4, if we know that the result obtained was an even number?
1. \(\frac 2 3\)
2. \(\frac 1 3\)
3. \(\frac 4 5\)
4. \(\frac 2 5\)
5. None of these

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Best answer
Correct Answer - Option 2 : \(\frac 1 3\)

Concept:

Conditional Probability: The probability of an event occurring given that another event has already occurred is called a conditional probability.

The probability of occurrence of any event A when another event B in relation to A has already occurred is known as conditional probability. It is depicted by P (A|B).

\({\rm{P}}\left( {{\rm{A}}|{\rm{B}}} \right) = \frac{{{\rm{P}}\left( {{\rm{A}} ∩ {\rm{B}}} \right)}}{{{\rm{P}}\left( {\rm{B}} \right)}}\)

Calculation:

Sample space is {1, 2, 3, 4, 5, 6}

Let A be the number obtained on dice is less than 4 and B is the number obtained on dice is even number.

A = {1, 2, 3} and B = {2, 4, 6}

P (A) = \(\frac 3 6\) and P (B) = \(\frac 3 6\)

Now, A ∩ B = {2}

P(A ∩ B) = \(\frac 1 6\)

Applying the conditional probability formula we get,

\({\rm{P}}\left( {{\rm{A}}|{\rm{B}}} \right) = \frac{{{\rm{P}}\left( {{\rm{A}} ∩ {\rm{B}}} \right)}}{{{\rm{P}}\left( {\rm{B}} \right)}} = \rm \frac{\frac{1}{6}}{\frac{3}{6}}=\frac{1}{3}\)

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