Correct Answer - Option 4 : 70
Given:
After passing each other, X and Y take \(8\dfrac{2}{5}\) hours and \(4\dfrac{2}{7}\) hours
The speed of X is 50 km/h
Concept Used:
If two trains start at the same time with speed x km/h and y km/h and after meeting they reached their destination in t1 hours and t2 hours then the relation between speed and time is \({x \over y} = \sqrt {t_2 \over t_1}\)
Calculation:
Here x = 50 km/h
t1 = \(8{2 \over 5}\) hours = 42/5 hours
t2 = \(4{2 \over 7}\) hours = 30/7 hours
Let, the speed of the train Y be a km/h
Accordingly,
\({50 \over a} = {\sqrt{{30 \over 7} \over {42 \over 5}}}\)
⇒ \({{50} \over a} = {\sqrt{{30 \times 5} \over {7 \times 42}}}\)
⇒ \({50 \over a} = \sqrt {5 \times 5 \over 7 \times 7}\)
⇒ 50/a = 5/7
⇒ a = 70
∴ The speed of the train Y is 70 km/hr.