Correct Answer - Option 1 : 40 W, 220 V
CONCEPT:
Electric power:
- The rate at which the electric energy is dissipated or consumed is termed electric power.
- The electric power is given as,
\(⇒ P=IV=I^{2}R=\frac{V^{2}}{R}\)
Where P = electric power, V = voltage, I = current and R = resistance
EXPLANATION:
Given P1 = 40 W, P2 = 60 W and V = 220 V,
- We know that for an electric bulb the resistance is given as,
\(⇒ R=\frac{V^{2}}{P}\)
\(⇒ R\propto\frac{1}{P}\) -----(1)
- For an electric bulb, the resistance of the bulb is inversely proportional to the power of the bulb.
- So the bulb which has more power will have low resistance, therefore the 40 W bulb will have more resistance compared to the 60 W bulb.
- Hence, option 1 is correct.