Correct Answer - Option 3 :
[ - \(\sqrt{2}\) , -2 ] ⋃ [ \(\sqrt{2}\) , 2 ]
Concept:
The domain and range of cos-1x are [ -1, 1 ] and [ 0, π ]
Calculation:
The domain of cos-1x is [ -1 , 1] .
Let y = cos-1 ( x2 -3 )
⇒ cos y = x2 - 3
As we know -1 ≤ cos θ ≤ 1
So, -1 ≤ cos y ≤ 1
⇒ -1 ≤ x2 - 3 ≤ 1
⇒ -1 + 3 ≤ x2 - 3 + 3 ≤ 1 + 3
⇒ 2 ≤ x2 ≤ 4
⇒ x2 ≥ 2 and x2 ≤ 4
So, x ∈ [-∞ , -√2] ∪ [ √2, ∞] and x ∈ [-2, 2]
From combining the above results, we get
⇒ -√2 ≤ x ≤ - 2 and √2 ≤ x ≤ 2
∴ x ∈ [ -√2 , -2 ] ⋃ [ √2 , 2 ]
The correct option is 3