Correct Answer - Option 2 :
\(\rm x^{\log x-1} (\log x^2)\)
Concept:
Formula:
log mn = n log m
\(\rm \frac{d(uv)}{dx} = v\frac{du}{dx}+u\frac{dv}{dx}\)
\(\rm \frac{d\log x}{dx} = \frac{1}{x}\)
\(\rm \frac{dx}{dx} = 1\)
Calculation:
Let y = xlog x
Taking log both sides, we get
⇒ log y = xlog x
⇒ log y = log x log x (∵ log mn = n log m)
Differentiating with respect to x, we get
⇒ \(\rm \frac{1}{y}\frac{dy}{dx} = \log x \frac{dlogx}{dx} + logx \frac{d\log x}{dx}\)
⇒ \(\rm \frac{dy}{dx} = y \left(\log x \times \frac{1}{x} + logx \times \frac{1}{x} \right )\)
⇒ \(\rm \frac{dy}{dx} = \frac{x^{\log x}}{x}\ (2\log x)\)
⇒ \(\rm \frac{dy}{dx} = x^{\log x-1} (\log x^2)\)