Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
94 views
in Calculus by (113k points)
closed by
Find derivative of (x)log x with respect to x
1. \(\rm x^{x-1} (\log x^2)\)
2. \(\rm x^{\log x-1} (\log x^2)\)
3. \(\rm x^{log \;x} (\log x^2)\)
4. None of these

1 Answer

0 votes
by (115k points)
selected by
 
Best answer
Correct Answer - Option 2 : \(\rm x^{\log x-1} (\log x^2)\)

Concept:

Formula:

log mn = n log m

\(\rm \frac{d(uv)}{dx} = v\frac{du}{dx}+u\frac{dv}{dx}\)

\(\rm \frac{d\log x}{dx} = \frac{1}{x}\)

\(\rm \frac{dx}{dx} = 1\)

Calculation:

Let y = xlog x

Taking log both sides, we get

⇒ log y = xlog x

⇒ log y = log x log  x            (∵ log mn = n log m)

Differentiating with respect to x, we get

⇒ \(\rm \frac{1}{y}\frac{dy}{dx} = \log x \frac{dlogx}{dx} + logx \frac{d\log x}{dx}\)

⇒ \(\rm \frac{dy}{dx} = y \left(\log x \times \frac{1}{x} + logx \times \frac{1}{x} \right )\)

⇒ \(\rm \frac{dy}{dx} = \frac{x^{\log x}}{x}\ (2\log x)\)

⇒ \(\rm \frac{dy}{dx} = x^{\log x-1} (\log x^2)\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...