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The area of  ΔABC whose vertices are A (x,2), B(2x,6), C(x,5) is 6, then what will be the value of x?


1. 4
2. 5
3. 6
4. 7

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Correct Answer - Option 1 : 4

As per Coordinate Geometry, the area of a triangle with vertices A(x1,y1), B(x2,y2), C(x3,y3)  is given by:

\(A =\frac{1}{2}[x_1(y_2-y_3) +x_2(y_3-y_1) +x_3(y_1-y_2)]\)

Putting values in the equation gives 

\(A=\frac{1}{2}[x(6-5)+2x(5-2)+x(2-6)]\)

\(A=\frac{\large3\large x}{\large2}\)

Given that area of the Δ is 6.

\(\therefore \frac{\large 3 \large x}{\large 2}=6\)

\(\therefore x=4\)

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