Correct Answer - Option 1 : 0.84C
Concept:
Contaminant concentration in stream immediately after mixing wastewater with stream water is given by,
\({C_{mix}} = \frac{{{C_w}{Q_w}\; + \;{C_s}{Q_s}}}{{{Q_w}\; + \;{Q_s}}}\)
Here, Cw = Contaminant concentration of waste water, Cs = Contaminant concentration of stream
Qw and Qs are discharges of treated wastewater and stream.
Calculation:
Given,
Cw = 5C, Cs = 0.01C, Qw = 0.2Q, Qs = Q
∵ We know that, \({C_{mix}} = \frac{{{C_w}{Q_w}\; + \;{C_s}{Q_s}}}{{{Q_w}\; +\; {Q_s}}}\)
\({C_{mix}} = \frac{{5C\; \times \;0.2Q \;+ \;0.01C\; \times \;Q}}{{0.2Q \;+\; Q}} = \frac{{CQ \;+\; 0.01CQ}}{{1.2Q}}\)
⇒ \({C_{mix}} = \frac{{1.01CQ}}{{1.2Q}} = 0.84C\)