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The population of a town was 1,80,000 three years ago, If it increased by 6%, 2.5% and 10% respectively in the last three years, then what is the present population?


1. 2,50,356
2. 1,98,586
3. 3,15,256
4. 2,15,127

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Correct Answer - Option 4 : 2,15,127

Given:

The population of a town was 1,80,000 three years ago,

In the last three years, the population increased by 6%, 2.5% & 10% respectively

Calculation

 Present population = 180000 × (1 + 6/100)(1 + 5/200)(1 + 10/100)

⇒ 180000 × 106/100 × 205/200 × 110/100 = 2,15,127

∴ The present population is 2,15,127

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