Correct Answer - Option 1 : 15 and 6
Given:
A = table of 3
B = table of 6
Concept used:
AUB = {All elements of A and B}
A∩B = {Common elements of A and B}
Calculation:
A = {3, 6, 9, 12, 15, 18, 21, 24, 27, 30}
B = {6, 12, 18, 24, 30, 36, 42, 48, 54, 60}
AUB = {All elements of A and B, but repeated one time}
AUB = {3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 36, 42, 48, 54, 60} = 15
A∩B = {Common elements of A and B}
A∩B = {6, 12, 18, 21, 24, 30} = 6
∴ (AUB) and (A∩B) are the number of elements respectively 15 and 6.
