Correct Answer - Option 2 : 8.84
Concept:
Relation between pre jump, post-jump and Froude number is given by,
\(\frac{{{y_2}}}{{{y_1}}} = \frac{1}{2}\left[ {\sqrt {1 + 8F_{r1}^2} - 1} \right] \)
Where,
y2 = Post jump depth
y1 = Pre-jump depth
F1 = Froude number before the jump
Calculation:
Given,
y2/y1 = 12
\(\frac{{{y_2}}}{{{y_1}}} = \frac{1}{2}\left[ {\sqrt {1 + 8F_{r1}^2} - 1} \right] = 12\)
252 = 1 + 8 Fr2
∴ Fr1 = 8.831